Determine if the reaction is spontaneous or not:

Question

a. 3 Li + Al ⟶ 3 Li + Al³⁺ E ̊ = - 1.39 V

Answer 1

If the Eº of the cell is negative, the reaction is NOT SPONTANEOUS.

Also, the reaction as written isn't possible since you have 3+ on the right side and no charge on the left.

Here are the possible reactions of Li and Al

3Li⁺(aq) + Al(s) ==> 3Li(s) + Al³⁺(aq) Eº = -1.39 V NOT SPONTANEOUS

or

3Li(s) + Al³⁺(aq) ==> 3Li⁺(aq) + Al(s) Eº = +1.39 V SPONTANEOUS