Daniel B. answered 05/23/22
A retired computer professional to teach math, physics
Let
r = 500 km = 5×105m be the radius of the asteroid,
d = 7×10³ kg/m³ be the density of the asteroid,
E = 100×4.184×1015 J = 4.184×1017 J be the energy released by the bomb,
v = 104 m/s be the velocity of the asteroid towards the Earth,
s = 101,000 km = 101×106 m be the distance from detonation to Earth,
R = 6.38×106 m be the radius of the Earth.
In the spirit of the given simplifying assumptions I will make more simplifying assumptions:
- Earth's gravity does not effect the asteroid,
- All the bomb's energy is converted into kinetic energy of the two halves,
pushing them in a direction exactly orthogonal to the asteroid's trajectory.
The time it take the asteroid (or its pieces) to reach the Earth is
T = s/v = 101×106/104 = 10100 s
The volume of the asteroid is
V = 4πr³/3
The mass of the asteroid is
m = Vd = 4πr³d/3 =
4×π×(5×105)3×7×103/3 = 3.665×1021 kg
The mass of each of the asteroid's halves is m/2.
Let w be the orthogonal velocity that the bomb imparts on each half.
The kinetic energy of each half (in the perpendicular direction) is (m/2)w²/2
This kinetic energy is equal half the bomb's yield:
mw²/4 = E/2
w = √(2E/m) = √(2×4.184×1017/3.665×1021) = 0.015 m/s
In time T each half covers the distance
Tw = 10100×0.015 = 152.6 m
Since 152.6 m is much smaller that the radius of the Earth,
the asteroid will strike the Earth.
Question 2:
Yes, we should hire miners, because in any hopeless situation the most valuable commodity is hope,
no matter how false.
But the give people hope we must stop teaching physics ;-)
Question 3:
Let
F = 3.92×1024 be the Superman's force.
I will assume that he pushes the asteroid in a direction perpendicular to its trajectory.
It gives the asteroid perpendicular acceleration
a = F/m
In time T, the asteroid will cover perpendicular distance
aT²/2 = FT²/2m =
3.92×1024×10100²/2×3.665×1021 = 5.5×1010 m
That gives must greater clearance than the radius of Earth -- 6,380 km -- plus the extra distance of 1290 km.