
Ashley P.
asked 05/20/223D Geometry: Intersection of Lines & Parallel Lines
Question:
Find the equations o the line that intersects the lines
2x + y - 1 = 0 = x - 2y + 3z (say 1)
3x - y + z - 2 + 2 = 0 = 4x + 5y - 2x - 3 (say 2)
and is parallel to the line x/1 = y/2 = z/3 (say 3)
=============================================
I noted that the RHS of (2) did not have a z coefficient, which I'm not sure is a typo, since this is how it was given in the question.
I had 2 approaches for this questions as follows:
(1) Equations of general lines passing through above are given by,
2x + y - 1 +k(x - 2y + 3z)----- (4) and
3x - y + z - 2 + 2 + r(4x + 5y - 2x - 3) ----(5) for some real number k &r
Let A & B be the points that the required line intersects (4) & (5).
Also, the required line is given to be parallel to the line x/1 = y/2 = z/3
So due to parallelism, the direction ratios of (3) & (4) and (3) & (5) should be in proportional at the points of intersection A & B.
i.e. (2+k)/1 = (1-2k)/2 = 3k/3 ---(6) and
(3+2r)/1 = (5r-1)/2 = 1/3 ---(7), which gives,
2+k=k from (6), which gives 2=0(??????)
Am I taking the right approach here?
1 Expert Answer

Dayv O. answered 05/21/22
Caring Super Enthusiastic Knowledgeable Geometry Tutor
I do think you can approach better, once the givens are typed coherently.
two planes intersect to form L1, put into form x1=a1t+x1, y1=b1t+y1, z1=c1t+z1
for the other two planes and L2, do the same with subscipts now =2 and use variable s instead of t
find a sure fire way to find L1 and L2. using simultaneous equations and putting z=0, then z=1
for the two planes in question will give points and slope ratios, but some way need to find L1 and L2.
Now the idea is to say x2-x1=f,,,y2-y1=2f,,,,,z2-z1=3f
what is next is a matrix wijth the variable vector as (s,t,f)T, the costant vector as (x2-x1,y2-y1,z2-z1)T
and matrix
row1=a2,,,a1,,,-1
row2=b2,,,b1,,,-2
row3=c2,,,c1,,,,-3
Should find valid s,t,f splving matrix equation
use t to find point on L1, use direction vector given to make line that is solution.
With the garbling of the question (who has +2-2, or 4x-2x as part of equation)
it is not possible to confidently find solution specifically.
Ashley P.
Could you give me a brief idea regarding taking the cross product here, as in the geometrical interpretation of why we take the cross product in the parallel case? Thank you!05/23/22

Roger R.
05/24/22
Still looking for help? Get the right answer, fast.
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Roger R.
05/20/22