Ashley P.

asked • 05/20/22

3D Geometry: Intersection of Lines & Parallel Lines

Question:


Find the equations o the line that intersects the lines

2x + y - 1 = 0 = x - 2y + 3z (say 1)

3x - y + z - 2 + 2 = 0 = 4x + 5y - 2x - 3 (say 2)

and is parallel to the line x/1 = y/2 = z/3 (say 3)


=============================================

I noted that the RHS of (2) did not have a z coefficient, which I'm not sure is a typo, since this is how it was given in the question.


I had 2 approaches for this questions as follows:

(1) Equations of general lines passing through above are given by,

2x + y - 1 +k(x - 2y + 3z)----- (4) and

3x - y + z - 2 + 2 + r(4x + 5y - 2x - 3) ----(5) for some real number k &r


Let A & B be the points that the required line intersects (4) & (5).

Also, the required line is given to be parallel to the line x/1 = y/2 = z/3


So due to parallelism, the direction ratios of (3) & (4) and (3) & (5) should be in proportional at the points of intersection A & B.

i.e. (2+k)/1 = (1-2k)/2 = 3k/3 ---(6) and

(3+2r)/1 = (5r-1)/2 = 1/3 ---(7), which gives,

2+k=k from (6), which gives 2=0(??????)


Am I taking the right approach here?

Roger R.

tutor
What class is this? Do you know how to interpret the numbers A, B, C, and D in the equation Ax +By +Cz +D = 0 of a plane geometrically? Do you know what the "k-procedure" you're applying is doing (again, in geometric terms)?
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05/20/22

Roger R.

tutor
Your conclusion "So due to parallelism, the direction ratios of (3) & (4) and (3) & (5) should be proportional at the points of intersection A & B." is false.
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05/20/22

Ashley P.

Class: 2nd year of university (i) Yes (ii) To the best of my understanding, what k-procedure does is giving an equation of a line that goes through any 2 given planes(in this case) (iii) So, in this case, we cannot take the direction ratios at the point of intersection to be proportional and can I ask why is that?
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05/20/22

Ashley P.

Or maybe, since (3) & (4) and (3) & (5) are parallel, maybe we can take the dot product of their direction ratios.
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05/20/22

Roger R.

tutor
Dot product is the way to go.
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05/20/22

Roger R.

tutor
Re k-procedure: The two planes share a common line g. The procedure chooses a new plane containing g. You "turn" a plane about g until it contains the line you're looking for, i.e. the given direction. With the dot product, you can find the necessary value for k.
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05/20/22

Ashley P.

Thank you! Now it all makes sense!
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05/20/22

Dayv O.

There must be a typo in your (say 2) right hand side. It must be 4x+5y-2z-3. Is that true?
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05/20/22

1 Expert Answer

By:

Dayv O. answered • 05/21/22

Tutor
5 (55)

Caring Super Enthusiastic Knowledgeable Geometry Tutor

Ashley P.

Could you give me a brief idea regarding taking the cross product here, as in the geometrical interpretation of why we take the cross product in the parallel case? Thank you!
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05/23/22

Roger R.

tutor
Hi Ashley, There are so many different ways to tackle this problem! When you post a question, please always add the course and topic. In this way, we can guess the intended learning objective of the problem and give an appropriate hint/answer. Dayv's approach uses a parameterization to describe a line, whereas you worked with pairs of cartesian equations F(x,y,z) = 0 & G(x,y,z) = 0. Parameterizations are super important, and you will have to make sure you can switch from one approach to the other w/o having to think a second about how to do that. The cross-product has different functions in the whole process. Dayv's answer indicates that he prefers to work with determinants, a powerful tool worth having in one's toolbox.
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05/24/22

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