An aerosol can has an internal pressure of 10 atm at 28 C what temperature is required if the final pressure is 20 atm??

Answer 1

Gay Lussac's law says that P1/T1 = P2/T2

Both P1 and T1 are given, but for chemical equations we don't use Celsius we use Kelvin since Kelvin sets 0 to absolute zero. To convert C to K the formula is C + 273 = K. So 28 becomes 301.

So P1/T1 = P2/T2 is 10 atm/301 K = 20 atm/T2.

You can solve this in two ways, but the ratio method is simpler here. 10 atm is half of 20 atm so 301 K must be half of T2. T2 therefore is 602 K. To convert that to celsius we use the same equation (K = 273 + C) which gives 329 oC.

Solving it algebraically should give the same result.