Mark M. answered 05/17/22
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Retired math prof. Very extensive Precalculus tutoring experience.
Let u = x15-7 Then du = 15x14dx So x14dx = (1/15)du
∫x29(x15-7)3/2dx = ∫x15(x15-7)3/2x14dx = ∫ (u+7)u3/2(1/15)du = (1/15)∫ [u5/2 +7u3/2]du
Apply the power rule