Tom N. answered 05/11/22
Strong proficiency in elementary and advanced mathematics
∫f(x)dx = 23 ∫x-3/5dx +C = 23(5/2)x2/5 + C. Taking the derivative of the new function gives 23(5/2)(2/5)x-3/5 which comes about by reducing the exponent by1.
Anjela R.
asked 05/11/22(Use symbolic notation and fractions where needed. Use 𝐶 for the arbitrary constant. Absorb into 𝐶 as muсh as possible.)
∫ 𝑓(𝑥) 𝑑𝑥 =
Tom N. answered 05/11/22
Strong proficiency in elementary and advanced mathematics
∫f(x)dx = 23 ∫x-3/5dx +C = 23(5/2)x2/5 + C. Taking the derivative of the new function gives 23(5/2)(2/5)x-3/5 which comes about by reducing the exponent by1.
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