how would you divide (6-q+8q cubed-4q squared)by (2q-2)

Question

please show the work

Answer 1

                     4q² + 2q + 3               
  (2q - 2)  l  _  8q³  -  4q²  -  q  +  6                                        
                     8q³  -  8q²                      
                            _  4q²  -  q   
                                4q² - 4q   
                                      _  3q  +  6  
                                         6q   +  6       
                                        -3q (remainder)  

   4q² + 2q + 3 -3q / (2q - 2)       

Answer 2

Get the polynomial in descending order, and divide divisor and dividend by 2 so synthetic division can be used.

 

 +1        |   4     -2     -1/2      3

                         4         2      3/2

                4       2       3/2     9/2

 

4q^2  +2q  +(3/2)  +(9/2)/(q - 1)