Find the area of ​​an isosceles triangle, if the height drawn on the base is 6 cm and the height drawn on the leg is 7.2 cm.

Answer 1

Area = 27 cm^2

sides are 9, 7.5 and 7.5 centimeters

angles are about 53.13, 53.13 and 73.74degrees

area = bh/2 = 9(6)/2 = 27

or = Lh/2 = 7.5(7.2)/2 = 27

let L = the length of each of two sides of the triangle and b= the base

b = 1.2L

sin(theta) = .6L/L =.6

theta = about 53.13 degrees

tan(53.13) = about 4/3

b/2/6 = 3/4

b/2 = 18/4

b =18/2 = 9 cm

L=1.2b = 7.5 cm