
Rei A.
asked 04/07/22Optimization Question about Profit, Demand, Revenue
I have a function of R(x) and C(x), which are income earned/Revenue function and cost function per week respectively.
For example, let's say:
R(x) = 310x + 0.02x^2 - 0.003x^3
C(x) = 3400 - 23x + 0.05x^2 + 0.0004x^3
I also have a profit function, that is P(x) = R(x) - C(x)
The main question is that if the manufacturing is increasing to 52 smartphones per week, and their current output is 130 smartphones, what is the rate that their profit will be increasing?
Thank you very much!
1 Expert Answer
Raymond B. answered 04/09/22
Math, microeconomics or criminal justice
I'm not certain exactly what the problem is asking, but for what it's worth here are some somewhat relevant calculations
R(x) = 310 + .02x^2 - .003x^3
C(x) = 3400 - 23x + .05x^2 + .0004x^3
P(x) = R(x) -C(x) = (.003-.0004)x^3 + (.02-.05)x^2 +23x + (310-3400)
take the derivative to find the rate of change in profit at production level of 130+54 = 184
P(x) = .0026x^3 -.03x^2 + 23x -3090
P'(x) = .0078x^2 -.06x +23
P'(184) = .0078(184)^2 - .06(184) + 23
= 264.0768 - 11.04+ 23
= 298.1168= $298.12 increase
P(130) = .0026(130)^3 -.03(130)^2 +23(130) -390
= 5712,2 - 507 + 2990 -390
= 7805.2
P(130+54) = .0026(184)^3 -.03(184)^2 +23(184) -390
= 16196.7104- 1015.68 + 4232 -390
= 19,023.030304
Profit increased by 11,217.8304 from 7,805.2 to 19,023.030304
298.12/19,023.030304 = about 2% per phone
which is a 11,217.8304/7,805.2 = 143,7225234%= about 144% increase in profit from 130 to 184
144/54 = about 2.7% rate of increase per cell phone
P(184)-P(130) = 11,217.8304
[P(184)-P(130)]/54 = 207.7376
P(184+54) = P(238) = .0026(238)^3 -.03(238)^2 +23(238) -390
= 35051.3072 - 1699.32 + 5474 -390
= 38,435.9872
P(238)- P(184) = 19,412.9569
[P(238) - P(184)]/54 = 359.4992019
(207.7376 + 359.4992019)/2 = 283.6184009
which equals close to P'(184) = 298.1168 =rate change at a point in time when x=130+54
283.6184009 = rate of change over an interval of x going from 130 to 130+54+54, with midpoint 103+54
if you found a smaller interval, plus & minuse 184, it should approach 298.1168
the answer you probably want is 298.1168 = P'(130+54) = the derivative of the profit function when x increases from 130 to 130+54
which is about a 144% increase in profits from x=130 to x=130+54, which is an average 144/54 = 2.67% increase in profit per cell phone
(no guarantees, arithmetic is error free)
Still looking for help? Get the right answer, fast.
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Luke J.
Did you mean "increasing BY 52 smartphones" and not "increasing TO 52 smartphones" ? Because it isn't an increase to 52 smartphones if they're already outputting 130 smartphones, it would technically be a decrease to 52 smartphones if phrased how your post says.04/07/22