one solution contains 1.6%, the other 6% salt. how much of each solution should be taken to get 550 g of a 4% saline solution?

Answer 1

.06x + .016(550-x) = .04(550)

.06x - .016x = .04(55) - .016(550)

.044x = .024(550)

x = .024(550)/.044 = 6(550)/11 = 6(50) = 300

x = 300 g of 6%

combined with

550-300 = 250 g of 1.6%

to get

550 g of 4%

6 is within 2 of 4

1.6 is within 2.4 of 4

2.4/2 = 1.2 = 300/250=6/5=1.2

you need 1.2 times as much 6% as 1.6%