
Yefim S. answered 03/30/22
Math Tutor with Experience
1) (2a - 3b)(a + b) = 2a2 + 2ab - 3ab - 3b2 = 2IaI2 - IaI·IbIcosθ - 3IbI2 = 2·12 - 1·4cosπ/3 - 3·42 = - 48
2) I2a - 3bI2 = (2a - 3b)2 = 4IaI2 - 12IaI·IbIcosθ + 9IbI2 = 4·12 - 12·1·4·cosπ/3 + 9·16 =124;
I2a - 3bI = 1241/2 = 2·311/2 = 2√31