Raymond B. answered 03/26/22
Math, microeconomics or criminal justice
7+5 = 12 have a dog, so 26-12 = 14 do not have a dog
probability of randomly selecting a student who does not have a dog = 14/26 = 7/13 about 53.8%
that's interpreting the problem as saying 14 have only a cat and 7 only a dog, with 5 having both.
but if you meant the problem to say 14 have a cat and 7 have a dog, and of those 21 students 5 have a cat and a dog, then 19 out of 26 do Not have a dog for probability 19/26 = about 73.1%