Inactive Tutor answered 03/21/22
let peak be at t=0
then in cos
v(t)=155.6cos(120πt),,,,,period =(1/60),,,,freq=2π/period
t=0, v=peak
in sin, must push peak at 1/240th second (phase shift) negative
v(t)=155.6sin(120π[t+1/240])
t=0,v=peak
Abby J.
asked 03/20/22Household electrical power in the US is provided in the form of alternating current. Typically, the voltage cycles smoothly between +155.6 volts and -155.6 volts 60 times per second. Use a sinusoidal function to model voltage, V, as a function of time, t, in seconds since the voltage was at its peak
V(t) = ?
Inactive Tutor answered 03/21/22
let peak be at t=0
then in cos
v(t)=155.6cos(120πt),,,,,period =(1/60),,,,freq=2π/period
t=0, v=peak
in sin, must push peak at 1/240th second (phase shift) negative
v(t)=155.6sin(120π[t+1/240])
t=0,v=peak
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