The length of a rectangular deck is 5 times its width. If the deck’s perimeter is 24 feet, what is the deck’s area?

Question

I need my answer because Branly won't help one 4th grader (which is me obviously).

Answer 1

Let l = length, w = width, area = A

given: l = 5w. and perimeter = 24

perimeter of rectangle = 2(l + w) = 2l + 2w

2l + 2w = 24

2(5w) + 2w = 24

12w = 24 => w = 2 ft

l = 5w = 5x2 = 10 ft

Area = l x w = 10 x 2 = 20 sq feet