J.R. S. answered 03/19/22
Ph.D. University Professor with 10+ years Tutoring Experience
KHP + NaOH⟶ H2O + NaKP ... balanced equation
0.299 g KHP x 1 mol KHP / 204.2 g = 0.004897 moles
If you titrated the entire 250.0 mls of KHP with NaOH, and it took 7.58 mls of NaOH (0.00758 L), then you can calculate the molar concentration of the NaOH as follows:
0.004897 mols KHP = 0.004897 mols NaOH / 0.00758 L = 0.646 M NaOH (3 sig. figs.)

J.R. S.
10/28/23
James P.
Shouldn't you use the number of mol present of KHP (0.004897 mol) in the given volume instead of converting to mol/L since there's a 1:1 molar ratio of KHP and NaOH?10/28/23