What is the velocity of a ball dropped from a height of 230 m when it hits the ground? Take the upward direction as positive.

Question

(Use decimal notation. Give your answer to three decimal places. Use 𝑔=9.8 m/s^2.)

𝑣≈ m/s

Answer 1

Given:

height (h)= 230 m

initial velocity (u) = 0 m/s ---> initially ball was at rest

final velocity (v) = ?

acceleration due to gravity (g)= 9.8 m/s²

since, we have to find the final velocity of the ball,

taking the upward direction as positive,

using the equation of motion:

v² = u² + 2gh

v² = 0² + 2 * 9.8 *230

v = sqrt (4508)

v = 67.14 m/s

Therefore, the velocity of the ball when it hits the ground is (v) = 67.14 m/s