Daniel B. answered 03/17/22
A retired computer professional to teach math, physics
Let
h = 6.5 m be the height of the column,
d = 1.5 m be the diameter of the column,
m = 60,500 kg be the mass of the slab,
g = 9.8 m/s² be gravitational acceleration,
E = 20×109 N/m² be Young's module.
The force, due to gravity, compressing the column is
F = mg
The horizontal cross section of the column is a circular disk with area
S = π(d/2)² = πd²/4
The stress is defined as
σ = F/S = 4mg/πd²
The strain is in linear relationship with the stress
ε = σ/E
By definition of strain, the deformation is
Δh = hε
Substituting actual values
(a) σ = 4×60500×9.8/(π×1.5²) = 335513 N/m²
(b) ε = 335513/20×109 = 16.7756×10-6
(c) Δh = hε = 6.5×16.7756×10-6 = 109.0416×10-6 m
That is about a tenth of a mm.
Sena K.
Thank you so much!03/24/22