Calculate the substrate concentration when this an enzyme has a Vmax of 1.2 𝜇M s−1. The Km for its substrate is 10 𝜇M.

Answer 1

This question doesn't really make any sense. The concentration of substrate to produce 1/2 Vmax is 10 uM, i.e the Km. To produce the Vmax, the [S] would have to be greater than 10x that, or > ~100 uM. What substrate concentration are you asking for?