Combining 0.281 mol Fe2O3 with excess carbon produced 14.2 g Fe. Fe2O3+3C⟶2Fe+3CO What is the actual yield of iron in moles?

Question

Combining 0.281 mol Fe2O3 with excess carbon produced 14.2 g Fe.

Fe2O3+3C⟶2Fe+3CO

What is the actual yield of iron in moles?

actual yield:____?____mol

What is the theoretical yield of iron in moles?

theoretical yield:___?___mol

What is the percent yield?

percent yield:___?___%

Answer 1

In the problem you are given the actual yield of 14.0g.

Theoretical yield is found by converting moles Fe2O3 to moles Fe then grams Fe. This gives you the amount of 62.76.

To find the percent yield you put the actual over theoretical and multiply by 100 which gives 22.6%.