Solve for the molarity of 0.327 grams sulfuric acid in a 250 ml solution.

Answer 1

1. Calculate the Molar Mass of H2SO4
2. Molar Mass H2SO4 = (2*Molar Mass H) + (1*Molar Mass S) + (4*Molar Mass O)
3. Molar Mass H2SO4 = (2*1.01 g/mol) + (1*32.07 g/mol) + (4*16.00 g/mol)
4. Molar Mass H2SO4 = 98.09 g/mol
5. Convert grams of H2SO4 to moles of H2SO4
6. Moles = (Grams) / (Molar Mass)
7. Moles = (0.327 g) / (98.09 g/mol)
8. Moles = 3.334*10^-3 moles of H2SO4
9. Determine the molarity by dividing moles of H2SO4 by the volume (in Liters) of solution
10. 250 mL = 0.25 L
11. Molarity = (Moles H2SO4) / ( L solution)
12. Molarity = (3.334*10^-3 moles H2SO4) / (0.25 L)
13. Molarity = 1.33*10^-2 M