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Question

You have combined the following: 7.74mL of 1.147M Fe(NO3)3(aq), 5.23mL of 1.976M NaCl(aq), and 7.13mL of water. What is the concentration of chloride ions in the resulting solution? Assume liquid volumes are additive and report your answer to 3 decimal places.

Answer 1

7.74 + 5.23 + 7.13 = 20.1 ml = 0.0201 l

Moles of Cl ions = (5.23 / 1000) x 1.976

So moles per l of Cl ions (1 / 0.0201) x ((5.23 / 1000) x 1.976 ) = 0.514 moles per L