Raymond B. answered 07/12/25
Math, microeconomics or criminal justice
Leo and Theo have $20's and $50 bills,
Leo gives Theo some 20's and T gives L an equal number of 50s
at this point L and T each have an equal amount of money
then T gives all the remaining six 50's to L and finally they end up with the reverse of where they started.
how many 20s did L give T? -10?
in the end T gives L six 50's = 6x50 = $300 more for Leo which is the reverse of the original situation
that means originally Theo had $300 more than Leo
then Leo exchanges 20s for an equal number of 50s leaving Leo worse off, not equal to Theo
unless you allow negative numbers. Leo gives Theo minus ten 20s for minus ten 50s
Unless someone else can come up with another interpretation of the problem.
the answer would be a positive ten if it were Leo giving Theo the six 50s at the end. It's easy to mix up Leo and Theo, so there may just be a mistake like that in the problem, mis-copied or misprinted.