Twice the difference of a number and 2 is greater than or equal to -15

Question

I need to turn this into an equation

Answer 1

2|x-2| = 2|2-x| > -15

"difference" usually means a non-negative number, so x could be any real number, as |x-2| is always positive or zero, and always greater than -15. the absolute value of 2(x-2) is always positive or zero, never negative

but if you did consider "difference" as being possibly negative then

2(x-2) > -15

2x -4 > -15

2x > -15+4

2x > -11

x > -11/2

x > - 5.5

or

2(2-x) > -15

4 -2x > -15

-2x > -19

divide or multiply by a negative number reverses the inequality

x < 19/2

x < 9.5

-5.5 < x < 9.5 is the solution that satisfies the inequality, however you interpret the problem