P(Y = 1) will equal 1 - P(y = -3 or -2 or 3 or 5)
mean is sum of (y * P(Y = y)) y - -3, -2, 1, 3 and 5
median is y value where cumulative frequency is 0.5
variance = sum [(y^2 * P(Y=y)] - mean^2
standard deviation is the square root of the variance
Mish L.
asked 02/13/22Suppose you are playing a game. The random variable, Y, represents your net profit in dollars. The probability
distribution of Y is as follows. (Round your answers to 4 decimal places, if needed.)
y -3 -2 1 3 5
P(Y=y) 0.15 0.13 ? 0.18 0.2
(a) What is the mean for net profit?
(b) What is the median for net profit?
(c) What is the standard deviation for net profit?
P(Y = 1) will equal 1 - P(y = -3 or -2 or 3 or 5)
mean is sum of (y * P(Y = y)) y - -3, -2, 1, 3 and 5
median is y value where cumulative frequency is 0.5
variance = sum [(y^2 * P(Y=y)] - mean^2
standard deviation is the square root of the variance
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