Raymond B. answered 02/11/22
Math, microeconomics or criminal justice
the answer is a) .033
getting all males out of 11 picks would be probability = 1/2048
getting just one woman would be 11/2048
getting two women out of 11 would be 55/2048
getting 2 or less women would be 67/2048 = about 0.033 or 3.3% chance
Pascal's triangle, 12th row, add the 1st 3, divide by sum of the entire 12th row
1
11
121
1331
14641
15101051
1615201561
172135352171
18285670562881
19-36-84-126-126-84-36-9-1
1-10-45-120-210-252-210-120-45-10-1
1-11-55-165-330-462-462-330-165-55-11-1
(1+11+55)/2048 = 67/2048 = about 0.0327 = about 0.033
11C0 = 1
11C1 = 11
11C2 = 11!/9!2! = 55
Pr(W<2) = (11C0+11C1+11C2)/(sum of 11C0 through 11C11)