Linear Inequalities Maximum Revenue

Question

Christy sells her photographs at a booth at a street fair. At the start of the day, she wants to have at least 25 photos to display at her booth. Each small photo she displays costs her $4 and each large photo costs her $10. She doesn't want to spend more than $200 on photos to display.

A. Find the maximum revenue if she sells each small photo for $10 & large for 20$

Please help :) TIA

Answer 1

Let x represented the small photo and y represented the large photo.

According to the question

4x+10y<200

x+y>25

Solving both equation for x and y

x=8 and y= 17

So total revenue is 420$.