Farzana I. answered 02/27/22
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Z = AB'C + A'B'C + A'BC + A'B'C + ABC
= AB'C + A'C (B' + B) + A'B'C + ABC
= AC(B' + B) + A'C.1 + A'B'C
= C (A + A') + A'B'C
= C (1 + A'B')
= C