Tom K. answered 01/06/22
Knowledgeable and Friendly Math and Statistics Tutor
a) yes
b) this would be all passwords minus those containing no vowels (or all consonants) =
26^3 - 21^3
c) n(A U B) = n(A) + n(B) - n(AB)
A = number starting with an A
B = number ending with a Z
AB = number beginning with an A and ending with a Z
A can have any second and third letter
B can have any first and second letter
AB can have any second letter
n(A) + n(B) - n(AB) =
26^2 + 26^2 - 26 =
26(26 + 26 - 1) = 26 * 51
Ka Fai K.
thanks for reply01/06/22