ALGEBRA HELP!!!The expression x^2-bx-c / x+b simplifies to x-6 whats the value of b?

Answer 1

If (x²-bx -c)/(x+b) = x-6, then x²-bx -c = (x-6)(x+b) = x² +(b-6)x - 6b.

Therefore, -b = b-6. Adding b and subtracting 6 at both sides we get 6 = 2b, so b=3.

Answer 2

(x² - bx - c)/(x +b) = x - 6

(x + b)[(x² - bx - c)/(x +b)] = (x - 6)(x + b)

x² - bx - c = x² + bx - 6x - 6b

- bx = (b - 6)x

÷ x. ÷ x

- b = b - 6

- b. - b

-2b = - 6

÷ -2 ÷ -2

b = 3

Extra Info:

Also, - c = -6b

- c = -6(3)

- c = - 18

c = 18