Jon S. answered 12/24/21
Patient and Knowledgeable Math and English Tutor
Ho: mu1 = mu2
Ha: mu1 != mu2
n1 = 49 xbar1 = 74 SD1 = 8
n2 = 49 xbar2 = 78 SD2 = 9
t = (xbar1 - xbar2)/sqrt(SD1^2/n1 + SD2^2/n2) = (74 - 78)/sqrt(64/49 + 81/49) = -2.33
p-value = P(t < -2.33)*2 at 7 DOF = 0.0263 *2 = 0.0526
since p-value > 0.01, then fail to reject Ho and it is reasonable to regard the two classes as having been obtained from the same normal population.