Patrick L. answered 12/23/21
AA in Mathematics with 7+ Years of Tutoring Experience
2a - 3b = -5
4a + 3b = 17
-2a + 5c = 1
1.) Add Equations 1 and 2 to find the value of a using the elimination method.
2a - 3b = -5
4a + 3b = 17
6a = 12
a = 2
2.) Substitute a = 2 in one of the two original equations to find the value of b.
2(2) - 3b = -5
4 - 3b = -5
-3b = -9
b = 3
3.) Substitute a = 2 in the third equation to find the value of c.
-2(2) + 5c = 1
-4 + 5c = 1
5c = 5
c = 1
The solution is (2, 3, 1).