
Pranav Kumar K. answered 12/25/21
CU Boulder Student
For cubic polynomial functions, the general form is (x-a)(x-b)(x-c) where a,b, and c are the x-values where y is zero. Thus, for zeroes of 1,2 and 3, the equation is f(x) = (x-1)(x-2)(x-3).
Aisha S.
asked 12/20/21Pranav Kumar K. answered 12/25/21
CU Boulder Student
For cubic polynomial functions, the general form is (x-a)(x-b)(x-c) where a,b, and c are the x-values where y is zero. Thus, for zeroes of 1,2 and 3, the equation is f(x) = (x-1)(x-2)(x-3).
Denise G. answered 12/20/21
Algebra, College Algebra, Prealgebra, Precalculus, GED, ASVAB Tutor
For the zeros, you have determine the factors that give you those zeros. Since they are all positive, they would all be subtraction.
f(x)=(x-2)(x-1)(x-3)
Multiply these together and you will have the polynomial.
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.