Raymond B. answered 12/13/21
Tutor
5
(2)
Math, microeconomics or criminal justice
L = 2W -2
L+W = 116/2 = 58
2W-2 + W = 58
3W = 58+2 = 60
W = 60/3 = 20 inches wide
L =2(20)-2 = 38 inches long
Sofi M.
asked 12/13/21the length of a rectangle is 2 inches less than twice the width. if the perimeter of the rectangle is 116 inches what are the dimensions
Raymond B. answered 12/13/21
Math, microeconomics or criminal justice
L = 2W -2
L+W = 116/2 = 58
2W-2 + W = 58
3W = 58+2 = 60
W = 60/3 = 20 inches wide
L =2(20)-2 = 38 inches long
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