f(x) = 3√x
f(29.16) = 16.2
f'(x) = 3/(2√x)
f'(29.16) = .27777777
Δx = - .16
f(29) ~ f(29.16) + f'(29.16) · Δx = 16.1555555555
Michael P.
asked 12/09/21f(x) = 3√x
f(29.16) = 16.2
f'(x) = 3/(2√x)
f'(29.16) = .27777777
Δx = - .16
f(29) ~ f(29.16) + f'(29.16) · Δx = 16.1555555555
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