60% alloy = 0.6 amount: x
30% alloy = 0.3. amount: 24 pounds
48% alloy = 0.48 amount: (x + 24 lbs)
0.6x + (0.3 * 24) = 0.48 (x + 24)
0.6x + 7.2 = 0.48x + 11.52
0.12x = 4.32
x = 36lbs of 60% alloy
Cameron F.
asked 12/06/21An aluminum alloy containing 48% aluminum is to be made by combining 30% and 60% alloy. How many pounds of the 60% alloy must be added to 24 pounds of the 30% alloy to produce the desired aluminum alloy?
60% alloy = 0.6 amount: x
30% alloy = 0.3. amount: 24 pounds
48% alloy = 0.48 amount: (x + 24 lbs)
0.6x + (0.3 * 24) = 0.48 (x + 24)
0.6x + 7.2 = 0.48x + 11.52
0.12x = 4.32
x = 36lbs of 60% alloy
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