Solve the following log questions for X.

Question

log(x+1)+e^(x+1)= 10

ln(x+1)+log(x+1)+log₄(x+1)=10

log(x+1)=log₄(x+1)

log(x-1)-4=log(10^(x-1))

Answer 1

log (x + 1) + e^{(x + 1)} = 10

log (x + 1) = 10 - e^{(x + 1)}

10^{(10 - e^(x + 1))} = 10

10 - e^{(x + 1)} = 1

-e^{(x + 1)} = -9

e^{(x + 1)} = 9

x + 1 = ln 9

x = ln 9 - 1

The rest are done in the same manner.