Inactive Tutor answered 11/20/21
Tutor
New to Wyzant
x2 + (√2/2 - 1/2)x - √2/4 = 0.
From here by Veet's Theorem x1 = 1/2, x2 = - √2/2.
A = 22 + 2 = 6;
B = (- √2 - 1) + (2 - 1) = - √2
Pedro S.
asked 11/20/21(E)... 4x² + (2√2 - 2)x - √2 = 0
We need to calculate A and B without Calculating x1 and x2 from (E)
A = (1/x1²) + (1/x2²)
B = (1/x2-1) + (1/x1-1)
Inactive Tutor answered 11/20/21
x2 + (√2/2 - 1/2)x - √2/4 = 0.
From here by Veet's Theorem x1 = 1/2, x2 = - √2/2.
A = 22 + 2 = 6;
B = (- √2 - 1) + (2 - 1) = - √2
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