J.R. S. answered 11/09/21
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
The specific heat for water (C) is 4.184 J/gº
The expression we use to calculate heat is q = mC∆T
q = heat = ?
m = mass = 550 g
C = specific heat = 4.184 J/gº
∆T = change in temperature = 18.0º - 12.0º = 6.0ºC
q = (550 g)(4.184 J/gº)(6.0º)
q = 13,807 J = 13,800 J (3 sig. fig.s)