Specific Heat Capacity Show work Please!

Question

When 5800 joules of energy are applied to a 15.2-kg piece of lead metal, how much does the temperature change by?

[2.98 degrees] <===Answer

Answer 1

You've asked several of these same type questions. The answer is usually found by using

q = mC∆T.

5800 J = (15.2 kg)(C for lead)(∆T)

∆T = 5.800 kJ / (15.2 kg)(C)

Look up the value for specific heat of lead (in kJ/kg/degree) and use it to find ∆T.