Let x = # of nickels, y = # of dimes, & z = # of quarters
Then x + y + z = 26
and 5x + 10y+ 25z = 300 if x = y (given)
2x + z = 26
15x + 25z = 300
Solving the 2 equations together, you find that x = 10, y = 10, z = (26 - 2x) = 6
T D.
asked 11/06/21Let x = # of nickels, y = # of dimes, & z = # of quarters
Then x + y + z = 26
and 5x + 10y+ 25z = 300 if x = y (given)
2x + z = 26
15x + 25z = 300
Solving the 2 equations together, you find that x = 10, y = 10, z = (26 - 2x) = 6
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