I think of a two digit number. The ones digit is 6 more than the tens digit. The number is 12 more than the product of its digits. Find the original number.

Answer 1

Let the number be xy

x must be a 1,2, or 3 based on the information given such that y is 6 more than x.

So the number must be 17, 28, or 39

The only number that meets the conditions is 28

The product of 2 & 8 is 16. Then 16 + 12 = 28