Specific Heat Capacity Show work Please!

Question

When 895-J of heat is applied to a sample of iron metal the temperature increases by 55.0 ∞C.Determine the mass of the metal sample to the nearest tenth of a gram.

[36.2g] <==== Answer

Answer 1

q = mC∆T

q = heat = 895 J

m = mass = ?

C = specific heat of iron = 0.45 J/gº (I looked it up. Your value may be different)

∆T = change in temperature = 55º

m = q/C∆T

m = 895 J / (0.45 J/gº)(55º)

m = 36.2 g