
Yefim S. answered 11/02/21
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2tanθ/(1 + tan2θ) = 2tanθcos2θ/[(1 + tan2θ)cos2θ] = 2sinθcosθ/(cos2θ + sin2θ) = sin2θ/1 = sin2θ
Rei A.
asked 11/02/21Verify the identity (2tanθ)/1+tan^2θ = sin2θ, given that trigonometric point P(θ)= (a,b). USE the given trigonometric point in the solution.
Yefim S. answered 11/02/21
Math Tutor with Experience
2tanθ/(1 + tan2θ) = 2tanθcos2θ/[(1 + tan2θ)cos2θ] = 2sinθcosθ/(cos2θ + sin2θ) = sin2θ/1 = sin2θ
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