An object is placed at the position x1 = 74 cm and a second mass that is 2 times as large is placed at x2 = 175 cm. Find the location of the center of mass of the system.

Answer 1

x = (m1*x1 + m2*x2) / (m1 + m2)

x = (m*74 + 2*m*175)/(m + 2m)

x = (74 + 2*175)/(3)

x = 141.33