f(x)=x^2-x+3, Find f(0), f(2), f(-4)

Answer 1

Hi John,

f(x) = x² - x + 3

The problem is to find the value for f(x) when x = 0, x = 2, and x = -4 so we can plug those values in to see what f(x) would be.

f(x) = x² - x + 3

f(2) = 2² - 2 + 3

f(2) = 4 - 2 + 3

f(2) = 2 + 3

f(2) = 5

Using this information, try and work through f(0) and f(-4). If you'd like to quickly check your answers, feel free to message me. Or if you'd like more help on math, I'm also available for sessions. :)

-Winn