An object dropped from a height of 140 meters hits the ground with velocity ______- units _______

Answer 1

v_f² = v_i² + 2gh where v_f is the final velocity, v_i is the initial velocity (in this case zero), g = -9.8 m/s² (the acceleration due to gravity), and h is the height (but it will be negative since the object is falling down away from the starting position). So:

v_f² = 0² + 2(-9.8)(-140)

v_f = √2744

v_f = 52.38 m/s