Write an equation in​ slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (-2,-8):y+-4x+1

Answer 1

Assuming you meant y = - 4x + 1 then we want a line with slope = - 4 (parallel lines have = slopes) that goes thru (-2 , -8).

The easiest way to get an equation is to use "point-slope" form of a line:

y + 8 = - 4 (x + 2) then rewriting in slope-intercept form requested

y = -4x - 16

OR finding b as follows: y = -4x + b

-8 = -4(-2) + b

b = -16

Answer 2

Hello!

I think you meant "y = -4x +1", correct?

If that's the case, this problem should be no problem!

As we know equations of lines that are parallel have the same slope. So the line you are looking for should have slope of -4. Let's put this in a slope-intercept form line equation (y=mx+b):

y = -4x + b, where m = slope = -4

Now we need to figure out what the y-intercept (b) is in that equation. If only we had a point whose x and y points we could plug in to solve for b...we do! (-2,-8) as provided in the question.

y = -4x + b

(-8) = -4(-8) + b

Once you solve for b, you should have a full equation that meets the requirements! Hope this help :)

Answer 3

Solution:

I am assuming that there is a typo in the above equation and it is actually y = -4x+1 not y+-4x+1

The equation of a line that is parallel to the above line have the same slope m = -4

The equation of the line in slope intercept form is y = mx + b with a slope of -4

y = -4x + b to find b substitute y and x in the equation from the point the line passes through (-2,-8)

-8 = -4(-2) + b, -8 = 8 +b , b= - 8 - 8= -16 , and y = -4x-16