Statistics Probability

Question

Thirty (30) students registered for a Statistics class; ten (10) men and twenty (20) women. Five (5) of the men and two (2) of the women are from out of town. For the following questions determine the answer by first justifying with the use of relevant formulae/explanation.

If a student is selected at random, what is the probability of selecting

(a) a male student?

(b) a male student, given that the student is from out of town?

(c) a male student, who is also from out of town?

(d) a male student or an out-of-town student?

Answer 1

Statistics Probability

Thirty (30) students registered for a Statistics class; ten (10) men and twenty (20) women. Five (5) of the men and two (2) of the women are from out of town. For the following questions determine the answer by first justifying with the use of relevant formulae/explanation.

If a student is selected at random, what is the probability of selecting

(a) a male student?

(b) a male student, given that the student is from out of town?

(c) a male student, who is also from out of town?

(d) a male student or an out-of-town student?

Hello Jay,

Just so you know, Statistics is mega-ultra-pull-your-hair-out-super boring, I have never had this class, but I tutor it all the time... LET'S GO BRANDON!

P(male) = 10/30 = 1/3

P(male | out of town) = 5/7

P(male ∩ out of town) = 5/30 = 1/6

P(male ∪ out of town) = P(male) + P(out of town) - P(male ∩ out of town)

*This problem means you need to add the probabilities of a male with the probability of the student being male or female from out of town, minus the probability of the student being a male from out of town.

P(male ∪ out of town) = P(male) + P(out of town) - P(male ∩ out of town)

P(male ∪ out of town) = 1/3 + 7/30 - 1/6 = 12/30 = 2/5

Any questions??