
Henoch M.
asked 10/15/21PLease help with this homework
Consider the function y(x) = − sqrt( 1 − x^2), the volume of the solid of revolution about the x-axis is :
a. Undefined
b. π
c. 4π/3
d. Cannot be solved using known techniques
1 Expert Answer

Bradford T. answered 10/16/21
MS in Electrical Engineering with 40+ years as an Engineer
y(x) = -√(1-x2)
V= π∫aby2dx = π∫-11 1-x2 dx = π[x-x3/3]-11 = π[1-1/3-(-1+1/3)] = 4π/3
Answer C.
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Michael F.
This website gives great advice: https://tutorial.math.lamar.edu/classes/calci/volumewithrings.aspx Your volume is the derivative of the area, which is denoted by pi*radius^2. Your radius is y(x). The function crosses the x axis at 1 and -1 so you would take the volume derivative from -1 to 1. The answer is C10/16/21