if x is IQ want to find
P(90 < x < 120)
transform inequality to standard normal (z), where z = (x - mean)/SD = (x -105)/15:
P( (90-105)/15 < z < (120-105)/15)
= P( -1 < z < 1)
= P(z < 1) - P(z < -1) = 0.8413 - 0.1587 = 0.6826
Bianka M.
asked 10/12/21Assume that adults have IQ scores that are normally distributed with a mean of μ=105 and a standard deviation σ=15. Find the probability that a randomly selected adult has an IQ between 90 and 120.
The probability that a randomly selected adult has an IQ between
90 and 120 is __.
if x is IQ want to find
P(90 < x < 120)
transform inequality to standard normal (z), where z = (x - mean)/SD = (x -105)/15:
P( (90-105)/15 < z < (120-105)/15)
= P( -1 < z < 1)
= P(z < 1) - P(z < -1) = 0.8413 - 0.1587 = 0.6826
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